In an ammeter 0.2% of main current passes
WebIn an ammeter 0.2 % of the main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be, from Physics Current Electricity … WebSolution In an ammeter 0.2 % of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be G 1 500 G. Explanation: …
In an ammeter 0.2% of main current passes
Did you know?
WebJan 30, 2024 · an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, then resistance of ammeter will be s-Advertisement Advertisement New questions in Computer Science. WebIn an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be A 1 499 G B 499 500 G C 1 500 G D 500 499 G Check Answer 2 NEET 2013 (Karnataka) MCQ (Single Correct Answer) + 4 - 1
WebIn an ammeter, 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, then the resistance of ammeter will be - A 1 499G B 499 500G C 1 … WebIn an ammeter, 0.2 % of main current passes through the galvanometer. If resistance of galvanometer is G , then the resistance of ammeter will be Q. 20 % of the main current …
WebMar 28, 2024 · It is given that the current through the galvanometer is 0.2% of the main current. Mathematically, I G = 0.2 % of I ⇒ I G = 0.2 100 × I ∴ I G = 0.002 I So, naturally, the … WebIn an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be 9539 83 AIPMT AIPMT 2014 Moving …
WebIn an ammeter 0.2 % of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be Medium Solution Verified by Toppr …
WebSolution In an ammeter 0.2 % of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be G 1 500 G. Explanation: n I I g n = I I g = 100 0.2 = 500 R G n ∴ R = G n G = G 500 Concept: Galvanometer Is there an error in this question or solution? in a christmas treeWebJun 17, 2024 · In an ammeter 0.2% of main current passes, through the galvanometer. If resistance of galvanometer is G , the resistance of ammeter will be: A 4991G B 500499G C 5001G D 499500G Difficulty level: easy Viewed by: 5,559 students Updated on: Mar 16, 2024 Solutions ( 26) 90 Share 25 students asked the same question on Filo in a city in ohio the sales tax rate is 7.25%WebJul 5, 2016 · in an ammeter 0 2% of main current passes through the galvanometer if resistance of galvanometer is G - Physics - Moving Charges And Magnetism - 10436227 Meritnation.com Class-12-science » Physics Moving Charges And Magnetism Sachin Dahake, asked a question Subject: Physics, asked on 5/7/16 ina hydrelWebJun 17, 2024 · In an ammeter 0.2 % of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be : A 4991G B 500499G C 5001G D 499500G Difficulty level: medium Viewed by: 5,264 students Updated on: Apr 1, 2024 Solutions ( 27) − − as (G) and the shunt are in parallel combination ina how easy is thatWebIn an ammeter 0.2 % of the main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be, 1/499 G 499/500 G 1/500 G 1/500 G 2526 Views Switch Flag Bookmark Advertisement Determine the current drawn from a 12 V supply with internal resistance 0.5 Ω by the infinite network shown in figure. ina il countyWebIn an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, then resistance of ammeter will be:- A 4991 G B 500499 G C 5001 G D … in a circuit voltage and current areWebJun 15, 2024 · In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, then resistance of ammeter will be :- ... The resistance of ammeter will be 1/499 G. Explanation: For ammeter: 0.0002 l x G = 0.9981 x rg. rg = 0.002 / 0.998 G. That is. rg = 0.002004 = 1/499 G. Hence the resistance of ammeter will be 1/499 G. in a circular flow model